Question

In the diagram below, the number in each box is the sum of the two numbers below it work out the missing numbers for boxes A,B and C Pls Answer them all

Answer 1

Answer:

B = 41/4

A = 5/2

Step-by-step explanation:

Given information:

• Number in each box = Sum of two numbers below it (Let it be the sum law)

As shown, number below B are 5 1/2 and 4 3/45

So, B = 5 1/2 + 4 3/4 (By sum law)

• B = 11/2 + 19/4 ... Convert the whole fractions into improper fractions
• B = 22/4 +19/4 = (22+19)/4 = 41/4

For 4 3/4 the numbers below it are A and 2 1/4

So according to the problem,by the sum law,

• 4 3/4 = A + 2 1/4
• 19/4 = A + 9/4 ... Convert whole fractions to improper fractions
• A = 19/4-9/4 ... Subtract 9/4 from both sides
• A = 10/4 = 5/2 ... Cancel 2

$\sf{\boxed{ \sf A = 5/2}}$

$\sf {\boxed{\sf B = 41/4}}$