Respuesta :
The obtuse angles will measure 120° and the acute angles will measure 60°.
Drawing the altitude forms a right triangle. Let the side of the rhombus be x. The altitude bisects the opposite side, so the base of the triangle formed would be 1/2x. We have an expression for the side opposite this portion of the obtuse angle (cut by the altitude) and for the hypotenuse (the side length of the rhombus, x). opposite/hypotenuse is the ratio for sine. Our equation then looks like this:
[tex]\sin x=\frac{\frac{1}{2}x}{x} \\ \sin x=\frac{1}{2}x \div x \\ \sin x=\frac{1}{2}x \div \frac{x}{1} \\ \sin x=\frac{1x}{2} * \frac{1}{x}=\frac{1x}{2x}=\frac{1}{2}[/tex]
Now we take the inverse sine of both sides:
sin⁻¹(sin x)=sin⁻¹(1/2)
x=30
Since this portion of the triangle is 30, and the right angle is 90, the missing angle (an acute angle of the rhombus) is 180-30-90=60°. Since the acute angles and obtuse angles of a rhombus are supplementary, the obtuse angles must be 180-60=120°.
Drawing the altitude forms a right triangle. Let the side of the rhombus be x. The altitude bisects the opposite side, so the base of the triangle formed would be 1/2x. We have an expression for the side opposite this portion of the obtuse angle (cut by the altitude) and for the hypotenuse (the side length of the rhombus, x). opposite/hypotenuse is the ratio for sine. Our equation then looks like this:
[tex]\sin x=\frac{\frac{1}{2}x}{x} \\ \sin x=\frac{1}{2}x \div x \\ \sin x=\frac{1}{2}x \div \frac{x}{1} \\ \sin x=\frac{1x}{2} * \frac{1}{x}=\frac{1x}{2x}=\frac{1}{2}[/tex]
Now we take the inverse sine of both sides:
sin⁻¹(sin x)=sin⁻¹(1/2)
x=30
Since this portion of the triangle is 30, and the right angle is 90, the missing angle (an acute angle of the rhombus) is 180-30-90=60°. Since the acute angles and obtuse angles of a rhombus are supplementary, the obtuse angles must be 180-60=120°.
The angles of the rhombus determines the inclination of the sides of the
rhombus.
The correct response;
- The measures of the four angles of the rhombus are 60°, 60°, 120°, and 120°.
Method used to arrive at the above response;
Given;
The altitude of the rhombus bisects the opposite side.
The angle of the rhombus at the vertex point of the altitude = An obtuse angle
Required:
The measure of the angles of the rhombus
Solution:
The length of the sides of a rhombus are equal.
The opposite angles of a rhombus are equal.
Let x represent the length of a side of the rhombus, we have;
The bisector from the vertex of the obtuse angle = An altitude
The angle the altitude forms with the side it bisects = 90°
Therefore;
The triangle formed by the altitude, half the bisected side and the side of the rhombus adjacent to the bisected side = A right triangle
The hypotenuse side to the right triangle = The side of the rhombus
Let θ represent the angle opposite the altitude, and between the sides of
the rhombus, in the right triangle by trigonometric ratios, we have;
- [tex]\displaystyle cos(\theta) = \mathbf{\frac{Adjacent}{Hypotenuse}}[/tex]
[tex]\displaystyle cos(\theta) = \frac{0.5 \cdot x}{x} = 0.5[/tex]
θ = arccos(0.5) = 60°
Therefore, two acute (opposite) angles of the rhombus are 60°
The two obtuse angles of the rhombus are each = (360° - 2×60°) ÷ 2 = 120°
- The angles of the rhombus are 60°, 60°, 120°, 120°.
Learn more about trigonometric ratios here:
https://brainly.com/question/1580944