Respuesta :
the equation for the reaction is as follows
H₂ + Cl₂ ---> 2HCl
the stoichiometry of Cl₂ to HCl is 1:2
this means that for every 1 mol of Cl₂ that reacts, 2 moles of HCl are produced.
Since there's excess of H₂, Cl₂ is the limiting reactant. Number of HCl moles produced are twice the number of Cl₂ moles reacted.
Mass of Cl₂ reacted = 7.25 g
Moles of Cl₂ reacted = 7.25 g / 70.9 g/mol
= 0.10 mol
moles of HCl produced - 0.10 mol x 2
= 0.20 mol
mass of HCl = 0.20 mol x 36.46 g/mol
= 7.29 g
H₂ + Cl₂ ---> 2HCl
the stoichiometry of Cl₂ to HCl is 1:2
this means that for every 1 mol of Cl₂ that reacts, 2 moles of HCl are produced.
Since there's excess of H₂, Cl₂ is the limiting reactant. Number of HCl moles produced are twice the number of Cl₂ moles reacted.
Mass of Cl₂ reacted = 7.25 g
Moles of Cl₂ reacted = 7.25 g / 70.9 g/mol
= 0.10 mol
moles of HCl produced - 0.10 mol x 2
= 0.20 mol
mass of HCl = 0.20 mol x 36.46 g/mol
= 7.29 g