Respuesta :
Number 6 is {{{y=4x^3 - 7}}} solve for x
{{{4x^3=y+7}}}
{{{x^3=(y+7)/4}}}
{{{x=root(3,(y+7)/4)}}}
{{{f^(-1)=root(3,(x+7)
And Number 7 is Replace
f
(
x
)
f
(
x
)
with
y
y
.
y
=
3
x
x
+
2
y
=
3
x
x
+
2
Interchange the variables.
x
=
3
y
y
+
2
x
=
3
y
y
+
2
Solve for
y
y
.
f
−
1
(
x
)
=
−
2
x
x
−
3
{{{4x^3=y+7}}}
{{{x^3=(y+7)/4}}}
{{{x=root(3,(y+7)/4)}}}
{{{f^(-1)=root(3,(x+7)
And Number 7 is Replace
f
(
x
)
f
(
x
)
with
y
y
.
y
=
3
x
x
+
2
y
=
3
x
x
+
2
Interchange the variables.
x
=
3
y
y
+
2
x
=
3
y
y
+
2
Solve for
y
y
.
f
−
1
(
x
)
=
−
2
x
x
−
3
6.) y = 3(4x+7)^(1/2)
Solve for x:
Square both sides:
y^2 = 9(4x+7)
y^2 = 36x + 63
y^2-63 = 36x
(y^2-63)/36 = x
Now swap x and y:
f^-1(x) = (x^2-63)/36
The above of the inverse function. However we need to restrict the domain since it does not pass the vertical line test. Since the original function has a range of y ≥ 0. The domain of our inverse is x ≥ 0.
You are only allowed 1 question per post, so I won't do the second question.
Solve for x:
Square both sides:
y^2 = 9(4x+7)
y^2 = 36x + 63
y^2-63 = 36x
(y^2-63)/36 = x
Now swap x and y:
f^-1(x) = (x^2-63)/36
The above of the inverse function. However we need to restrict the domain since it does not pass the vertical line test. Since the original function has a range of y ≥ 0. The domain of our inverse is x ≥ 0.
You are only allowed 1 question per post, so I won't do the second question.