Respuesta :
x-4/2x=3x/2x-1 (invert the bottom and then multiply)
x-4 (2x+3x/2x-1) ( the 2x's cancel)
x-4 (3x/-1)
x-4 (-3x) (expand)
-3x^2 + 12x=0
-3x^2= -12x (bring 12x to other side making it negative)
-3x^2/3x= -12x/-3x (divide both sides by -3x)
x=4
Hope that helps
x-4 (2x+3x/2x-1) ( the 2x's cancel)
x-4 (3x/-1)
x-4 (-3x) (expand)
-3x^2 + 12x=0
-3x^2= -12x (bring 12x to other side making it negative)
-3x^2/3x= -12x/-3x (divide both sides by -3x)
x=4
Hope that helps
[tex] \frac{2x-1}{x} + \frac{x}{x -2} = \frac{(2x-1)(x-2) +(x)(7x)}{(7x)(x-2)}[/tex]
You know the first term of the numerator wil be 2x^2 +7x^2 = 9x^2, and the last term of the denominator will be 7x(-2) = -14x.
This is sufficient work to identify selection B as the correct choice.
You know the first term of the numerator wil be 2x^2 +7x^2 = 9x^2, and the last term of the denominator will be 7x(-2) = -14x.
This is sufficient work to identify selection B as the correct choice.