Answer:
The probability that the product of the two numbers is a composite number
[tex]P(E) = \frac{5}{6}[/tex]
Step-by-step explanation:
Step(i):-
Given data Two fair six-sided dice are rolled
S = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6) ,(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),((4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
The number of exhaustive cases
n(S) =36
Composite number :-
A composite number has more than two factors
Example :-
Find composite numbers 1 to 10
{ 4, 6, 8.9,10}
Step(ii):-
Let 'E' be the event of getting the product of the two numbers is a composite number
= {(1,4),(1,5),(1,6),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,3),(3,4),(3,5),(3,6),((4,1),(4,2),(4,3),(4,4),(4,5),(4,6)(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
n(E) = 30
Conclusion:-
The probability that the product of the two numbers is a composite number
[tex]P(E) = \frac{n(E)}{n(S)} = \frac{30}{36} = \frac{5}{6}[/tex]
