Question

what is a solution to the inequality-3x + 5 < 20

Answer 1

Solve for 'x':

$\sf -3x+5<20$

Subtract 5 to both sides:

$\sf -3x<15$

Divide -3 to both sides(be sure to switch the sign, we do this when multiplying/dividing by a negative number):

$\sf x>-5$

So any number greater than -5 will be a solution.