What is the mass of a sample of iron if that sample lost 2300J of heat energy when it cooled from 80 oC to 30°C? The specific heat of iron is 0.449 J /g °C.
102 grams. Equation: Quantify of heat = mass x specific heat x difference in temperature We have: quantity of heat : 2300J specific heat: .449 J/g difference in t: 80 - 30 = 50 Solve for mass: 2300 = mass x 0.449 x 50 mass = 102.449 2 sig-figs --> 102 grams
