Question

What is the factorization of the trinomial below 14x2 - 39x - 35?

Answer 1

14x^2 - 39x - 35

= 14x^2 - 49x + 10x - 35

= 7x(2x - 7) + 5(2x - 7)

= (7x + 5)(2x - 7) Answer

Answer 2

Answer:

The factored form of  the given trinomial $14x^2-39x-35$  is $(7x+5)(2x-7)$

Step-by-step explanation:

Given trinomial $14x^2-39x-35$

We have to write the given trinomial $14x^2-39x-35$ in factored form.

Consider the given trinomial $14x^2-39x-35$

Factorization is the process in which we write a given polynomial in form of factors using multiplication.

We will solve the given polynomial using middle term split method,

Split middle term in such a way that the the product of term is the product of its remaining terms.

-39x can be written as 10x - 49x

Thus, the polynomial is written as

$14x^2+10x-49x-35$

Taking 2x common from first two term and -7 common from last two terms , we have,

$2x(7x+5)-7(7x+5)$

Again taking (7x + 5) common from both terms, we have,

$(7x+5)(2x-7)$

Thus, The factored form of  the given trinomial $14x^2-39x-35$  is $(7x+5)(2x-7)$