Respuesta :
correct answers are D, A, A, B, A
1) V1/T1=V2/T2 --> V2 = V1x(T2/T1) = 300cm³ x (333K/303K) = 330cm³ (assuming constant P)
2) V1/T1=V2/T2 -->V1=V2x(T1/T2) = 1.0Lx(300K/100K) = 3.0L
3) you have 2x as many moles of antacid ---> 2x as many moles of gas...V1/n1 = V2/n2 ---> V2 = V1 x (n2/n1).. double the moles, double the volume... so gas from 4 tablets > gas from 2 tablets.
4) P1/T1=P2/T2 ---> P2=P1x(T2/T1)..if T was left in °C, P2=100kPax(10°C/60°C) = 17kPa. T MUST be in absolute temperature. either K or R. never °F nor °C. units of P do not matter.
5).. constant T,n = boyles, constant P,n = charles, constant V,n = Gay-Lussac's
1) V1/T1=V2/T2 --> V2 = V1x(T2/T1) = 300cm³ x (333K/303K) = 330cm³ (assuming constant P)
2) V1/T1=V2/T2 -->V1=V2x(T1/T2) = 1.0Lx(300K/100K) = 3.0L
3) you have 2x as many moles of antacid ---> 2x as many moles of gas...V1/n1 = V2/n2 ---> V2 = V1 x (n2/n1).. double the moles, double the volume... so gas from 4 tablets > gas from 2 tablets.
4) P1/T1=P2/T2 ---> P2=P1x(T2/T1)..if T was left in °C, P2=100kPax(10°C/60°C) = 17kPa. T MUST be in absolute temperature. either K or R. never °F nor °C. units of P do not matter.
5).. constant T,n = boyles, constant P,n = charles, constant V,n = Gay-Lussac's
.3 m 3. 2. In an isothermal process, a mass of gas has its volume reduced from 50 cm3 to 32 cm3 . If the initial pressure of the gas is 80 kPa, determine its final .... 300. = 141 kPa. 2. A pressure vessel is subjected to a gas pressure of 8 atmospheres at a temperature of 15ºC. The vessel can withstand a maximum pressure of