Question

A typical neutron star may have a mass equal to that of the sun but a radius of only 20 km. (a) what is the gravitational acceleration at the surface of such a star? (enter the magnitude.)

Answer 1

 You will have to google these constants for yourself. I am warned not to give you the references.
Givens
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The given constant acceleration of the sun = 273.7 m/s^2
The Radius of the sun = 695,700 km 
Radius of the star = 20 km
acceleration on the star's surface = a1

Formula
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m_test * a_sun = G * m_test * mass_sun /( r_sun)^2
=========== . . .=========================
m_test * a_sun. . . G* m_test* mass_star / (r_star)^2

There is a lot oc cancellation. The result is.
a_sun / a_star = (r_star)^2 / r^2 Now all you have to do is substitute

Calculations
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273.7 / a _ star = (20 000)^2 / (695700 )^2
a_star = 273.7 * (695700)^2 / (20000)^2

a_star = 331176 m/s^2 which is pretty big

Answer 2

The value of acceleration due to gravity on the surface of the neutron star will be  $\boxed{3.335 \times {{10}^{11}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}$.

Further Explanation:

Given:

The mass of the star is same as the mass of the sun i.e.  

The radius of the star is  .

Concept:

The acceleration due to gravity on the surface of a planet is given by the Newton’s law of gravitation.

The Newton’s law of gravitation states that the force experienced by a body on the surface of a planet or a star is directly proportional to the product of the mass of the planet and the body and inversely proportional to the square of the distance between the center of planet and the body (i.e. the radius).

It is expressed mathematically as:

$\boxed{{F_g} = \frac{{GMm}}{{{R^2}}}}$

Here, ${F_g}$ is the gravitational force, $G$ is the gravitational constant, $M$ is the mass of the planet/star, $m$ is the mass of the body kept on the planet/star and $R$ is the radius of the planet/star.

The weight of a body is the force experienced by the body due to the gravitational pull. The force experienced by a body of mass $m$ is represented as:

${F_g} = mg$

Substitute $mg$ for ${F_g}$ in above expression of gravitational force.

$\begin{aligned}mg&= \frac{{GMm}}{{{R^2}}}\hfill\\g&= \frac{{GM}}{{{R^2}}}\hfill\\\end{aligned}$

Substitute the value of the mass and the radius of the star in the above expression.

$\begin{aligned}g&=\frac{{\left( {6.67 \times {{10}^{ - 11}}} \right)\left( {2 \times {{10}^{30}}} \right)}}{{{{\left( {20000} \right)}^2}}}\\&=\frac{{1.334 \times {{10}^{20}}}}{{4 \times {{10}^8}}}\\&= 3.335 \times {10^{11}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}\\\end{aligned}$

Thus, the value of acceleration due to gravity on the surface of the neutron star will be $\boxed{3.335 \times {{10}^{11}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}$.

Learn More:

1. Suppose our experimenter repeats his experiment on a planet more massive than earth, where the acceleration due to gravity is g=30 m/s2 https://brainly.com/question/10934170

2. If forces acting on an object are unbalanced, the object could experience a change in, direction, or both https://brainly.com/question/2720955

3. Calculate the total force on the earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line https://brainly.com/question/2887352

Answer Details:

Grade: High School

Subject: Physics

Chapter: Gravitation

Keywords:  Typical neutron star, mass, equal to that of sun, radius, 20 km, gravitational acceleration, Newton’s law of gravitation, force of gravity, F=mg.