Question

If the hypotenuse of a 45 45 90 triangle is 8 what is one of the legs

Answer 1

   
$\displaystyle \bf \\ \text{One of the legs} = \frac{hypotenuse}{ \sqrt{2}} = \frac{8}{ \sqrt{2}} = \frac{8\sqrt{2}}{ 2} =\boxed{\bf 4\sqrt{2}}$