Respuesta :
Answer is: precipitation requires fewer Ag⁺ ions in AgBr than in AgCl.
Chemical reactions:
Ksp(KBr) = 5,3·10⁻¹³.
Ksp(KCl) = 1,8·10⁻¹⁰.
Ksp is solubility product constant. The higher the Ksp value, substance is more soluble. KBr has lower Ksp, so it is easier to form precipitant of KBr than KCl.
Chemical reactions:
Ksp(KBr) = 5,3·10⁻¹³.
Ksp(KCl) = 1,8·10⁻¹⁰.
Ksp is solubility product constant. The higher the Ksp value, substance is more soluble. KBr has lower Ksp, so it is easier to form precipitant of KBr than KCl.
Answer:
C
Explanation:
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