Question

condense the logarithm expression 100 points

Answer 1

(1/2)[logb(b^2)+logb(8x)]

=(1/2)[2+logb(8x)]

=1+(1/2)logb(8x)

hope this helps you

Answer 2

Answer:

I agree with the person above me!

Step-by-step explanation:

(1/2)[logb(b^2)+logb(8x)]

=(1/2)[2+logb(8x)]

=1+(1/2)logb(8x)