Answer:
2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)
Explanation:
Let's consider the double displacement reaction in which aqueous silver nitrate reacts with aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate.
AgNO₃(aq) + NiCl₂(aq) ⇒ AgCl(s) + Ni(NO₃)₂(aq)
We have 2 atoms of Cl on the left side, so we will add a stoichiometric coefficient 2 to AgCl.
AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)
Now, we have 2 atoms of Ag on the right side, so we will add a stoichiometric coefficient 2 to AgNO₃.
2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)
Now, the equation is balanced.
The balanced chemical equation for the reaction is
2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)
To write a balanced chemical equation for the reaction between aqueous silver nitrate and aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate
First, we will write the chemical formula for the each of the reactants and products
That is,
Silver nitrate - AgNO₃
Nickel(II) chloride - NiCl₂
Silver chloride - AgCl
Nickel(II) nitrate - Ni(NO₃)₂
Now, for the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)
Hence, the balanced chemical equation for the reaction is 2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)
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