we are given system of equation as
[tex] 3d-e=5 [/tex]
[tex] 7d+e=5 [/tex]
We are given linear combination method
In linear combination method , we always try to cancel one variable by combining two equations
step-1: Add both equations
[tex] 3d-e=5 [/tex]
[tex] 7d+e=5 [/tex]
-----------------------------------
[tex] 7d+3d=5+5 [/tex]
[tex] 10d=10 [/tex]
step-2: Divide both sides by 10
[tex] \frac{10d}{10} =\frac{10}{10} [/tex]
[tex] d=1 [/tex]
step-3: Solve for e
[tex] 7d+e=5 [/tex]
we can plug d=1
[tex] 7*1+e=5 [/tex]
[tex] 7+e-7=5-7 [/tex]
[tex] e=-2 [/tex]
so, solution is (d,e)=(1,-2)..........Answer