Respuesta :

[tex]\\f(x)=\sqrt{x-2} \\ \\g(x)=(x-1)^2+2[/tex]

Answer:

[tex]y=\sqrt{x-2}[/tex]

Step-by-step explanation:

[tex]y=\sqrt{x-2}[/tex]

Let us see how.

Our function contains a square root. And we know that we can not find the square root of any negative number as a square always gives you a positive number . Hence reverse can not be possible. Thus

we have (x-2) under square root. thus this number must be greater than or equal to 0

(x-2)≥0

subtracting 2 from both sides we get

x≥2

Hence our function gives result only for values which are greater than or equal to 2. Or the domain of function is [2,∞]