[tex]so \: the \: formula \: of \: the \: area \: of \: a \: circle \: is \: given \: by \: \pi{r}^{2} \\ r \: is \: the \: radius \: of \: the \: diameter \\ to \: find \: the \: radius \: you \: take \: ur \: diameter \: and \: divide \: it \: by \: 2 \\ so \: if \: ur \: diameter \: is \: 10 \: then \: ur \: radius \: would \: be \: 5 \\ with \: that \: you \: can \: apply \: it \: to \: the \: formula \: given \: and \: that \: is \: \pi {5}^{2} \\ btw \: if \: you \: dont \: know \: the \: value \: of \: \pi \: it \: is \: 3.142 \: or \: \frac{22}{7} so \: just \: sub \: that \: in \: and \: you \: will \: get \: ur \: answer \: by \: using \: ur \: calculator[/tex]
