Respuesta :
Answer : The correct option is, (4) increased temperature and decreased pressure
Explanation :
The conditions for ideal gas are, it has no intermolecular attractions and have negligible volume.
The ideal gas equation is,
[tex]PV=nRT[/tex]
The conditions for real gas are, it has intermolecular attractions and have volume.
The real gas equation is,
[tex](P+\frac{an^2}{V^2})(V-nb)=nRT[/tex]
A real gas behave ideally at high temperature and low pressure conditions.
From the given options, option (4) increased temperature and decreased pressure is the correct option.
Hence, increased temperature and decreased pressure this sample to behave more like an ideal gas.
Answer : The correct option is, (4) increased temperature and decreased pressure
Explanation :
The ideal gas conditions are :
These are those gas that has no intermolecular attractions.
These are those gas that have negligible volume.
The ideal gas equation is,
[tex]PV=nRT[/tex]
The real gas conditions are :
These are those gas that have intermolecular attractions.
These are those gas that have volume.
The real gas equation is,
[tex](P+\frac{an^2}{V^2})(V-nb)=nRT[/tex]
As we know that a real gas behave ideally at high temperature and low pressure condition.
Hence, the correct option is, (4) increased temperature and decreased pressure
