Question

A small boat sailed straight north out of a harbor in strong east wind (blowing from west to east). After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km, what is the speed of the east wind?.

Answer 1

it can be said that  the speed of the east wind is

v=0.3608m/s

From the question we are told

A small boat sailed straight north out of a harbor in strong east wind (blowing from west to east).

After sailing for 120 minutes, it ended up hitting a buoy 60^\circ60 ∘ to the north-east of the harbor. If the straight-line distance between the buoy and the harbor is 3 km,

• what is the speed of the east wind?.

the speed of the east wind

Generally the equation for the distance  is mathematically given as

BA=3000sin60

BA=2598.07m

Therefore

the speed of the east wind

$V_w=\frac{BA}{120*60}\\\\V_w=\frac{2598.07}{120*60}$

v=0.3608

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