Question

The width of a rectangle is 6 2/3 inches. The length of the rectangle is twice its width. What is the perimeter of the rectangle

Answer 1

A perimeter of a rectangle is:
$2(l+w)$

They give you the width, but let's convert it to an improper fraction first:
$6 \frac{2}{3} = \frac{20}{3}$

The length is twice the width so it is:
$\frac{20}{3}*2 = \frac{40}{3}$

Now, we are ready to solve, plug in values in the perimeter formula:
$2( \frac{40}{3}+ \frac{20}{3}) = 2(\frac{60}{3}) = \frac{120}{3} = 40$

So, 40 is your answer.

Answer 2

The Perimeter of the Rectangle was found to be 40 inches

Mensuration of flat Shapes

Given Data

• Width =  6 2/3 inches  = 20/3 inches

• Length =  20/3 *2 = 40/3

We know that the expression for finding the Perimeter of Rectangle is given as

Perimeter = 2L+2W

Substituting our data into the expression we have

Perimeter = 2(20/3)+2(40/3)

Perimeter = (40/3)+(80/3)

Perimeter = (40+80)/3

Perimeter = 120/3

Perimeter = 40 inches

Learn more about rectangles here:

https://brainly.com/question/25292087