julicey9592 julicey9592
  • 29-12-2017
  • Mathematics
contestada

The perimeter of a rectangle is 100 yd. if its width is four times its length, what is the area?

Respuesta :

shinmin
shinmin shinmin
  • 10-01-2018

Length = l


Width = w


Perimeter = p = 100

Perimeter of rectangle = 2(l+w)


100 = 2 (4w + w)


100 = 2(5w)


100 = 10w


100/10 = w


10 = w


w =  10



Area of rectangle = length * width


a = l*w

a = 4w*w


a = 4w^2............(1)


Put the value of w in (1)


a = 4(10)^2


a= 4(100)


a = 400 yd^2

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