Question

8^(3x-1)=2^8 

Solve for x 

Answer 1

$8^{3x - 1} = 2^8 ; 8 = 2^3 \\ (2^3)^{3x-1} = 2^8 \\ 2^{9x-3} = 2^8 \\ 9x-3=8 \\ 9x=11 \\ x= \frac{11}{9}$

Answer 2

$8^{(3x-1)}=2^8 \\\\ 2^{3(3x-1)}=2^8 \\\\ 3(3x-1)=8 \\\\ 9x-3=8 \\\\ 9x=8+3 \\\\ 9x=11 \\\\ \boxed{x=\frac{11}{9}}$