Question

What is the percent by mass of carbon in acetone, c 3 h 6 o?

Answer 1

In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol

To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=$( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%$
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%

Answer 2

Answer: I just took the test and got 100%

1. B: 0.430 mol

2. B: percent composition

3. C: 71.5%

4. B: 62.1%

5. A: empirical formula

6. D: C16H24O4

7. D: 673g

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