Question

What is the mass, in grams, 6.5 mol of sodium nitrate (nano3)? please show all work?

Answer 1

Mass is the property of a physical body and the resistance to acceleration when a net force is applied on the body.  
The atomic mass of sodium (Na) is = 22.98 
The atomic mass of nitrate (N) is = 14.00 
The atomic mass of oxygen (O) is = 15.99  
The sodium nitrate (NaNO3) consists of the atomic masses of Na+N+(O)3 = 85 grams  
Therefore, the mass of 6.5 mol of sodium nitrate is = 6.5 * 1 mol of NaNO3 
 = 6.5 * (85) 
 = 552.50 grams

Answer 2

The mass (in grams) of 6.5 mol of sodium nitrate is $\boxed{552.24{\text{ g}}}$.

Further Explanation:

The measure of the amount of substance is defined as mole. It is the mass of a substance that fundamental units as there are atoms in 12 g of carbon-12. These fundamental units can be atoms, molecules or formula units.

Molar mass is defined as the sum of the total masses of all the constituent atoms present in a molecule. It is also known as molecular weight and its unit is grams per mole.

The formula to calculate the molar mass of sodium nitrate is as follows:

${\text{Molar mass of NaN}}{{\text{O}}_{\text{3}}}&= \left[ \begin{aligned}{\text{1}}\left( {{\text{Atomic mass of Na}}} \right)+ \\{\text{1}}\left( {{\text{Atomic mass of N}}} \right)+ \\{\text{3}}\left( {{\text{Atomic mass of O}}} \right)\\\end{aligned}\right]$                                ...... (1)

The atomic mass of Na is 22.99 g.

The atomic mass of N is 14 g.

The atomic mass of O is 15.99 g.

Substitute these values in equation (1).

 $\begin{aligned}{\text{Molar mass of NaN}}{{\text{O}}_{\text{3}}} &= \left[ {{\text{1}}\left( {{\text{22}}{\text{.99 g}}} \right) + {\text{1}}\left( {{\text{14 g}}} \right) + {\text{3}}\left( {{\text{15}}{\text{.99 g}}} \right)} \right]\\&= \left[ {{\text{22}}{\text{.99 g}} + {\text{14 g}} + 47.97{\text{ g}}} \right]\\&= 84.96{\text{ g/mol}}\\\end{aligned}$

The molar mass of ${\text{NaN}}{{\text{O}}_{\text{3}}}$ comes out to be 84.96 g. This implies this is the mass of one mole of ${\text{NaN}}{{\text{O}}_{\text{3}}}$.

Therefore the required mass of ${\text{NaN}}{{\text{O}}_{\text{3}}}$ can be calculated as follows:

 $\begin{aligned}{\text{Mass of NaN}}{{\text{O}}_{\text{3}}} &= \left( {6.5{\text{ mol}}} \right)\left( {\frac{{84.96{\text{ g}}}}{{1{\text{ mol}}}}} \right)\\&= 552.24{\text{ g}}\\\end{aligned}$

So the mass of ${\text{NaN}}{{\text{O}}_{\text{3}}}$ is 552.24 g.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
2. Calculate the moles of ions in the solution: https://brainly.com/question/5950133

Answer Details:

Grade: Senior School

Chapter: Mole Concept

Subject: Chemistry

Keywords: sodium nitrate, mass, grams, molar mass, NaNO3, atomic mass, N, O, Na, 15.99 g, 22.99 g, 14 g, molar mass of NaNO3, 555.24 g, mole, atoms, 12 g, carbon-12, 84.96 g/mol.