Question

One drawer in a dresser contains 8 blue socks and 6 white socks. a second drawer contains 3 blue socks and 5 white socks. one sock is chosen from each drawer. what is the probability that they match

Answer 1

The probably would be a chance of matching 74%

Answer 2

Drawer 1: P(blue) = 8/14            P(white) = 6/14
Drawer 2: P(blue) = 3/8              P(white) = 5/8
$P(blue/blue)=\frac{8}{14}\times\frac{3}{8}=\frac{3}{14}$
$P(white/white)=\frac{6}{14}\times\frac{5}{8}=\frac{15}{56}$
$P(match)=\frac{3}{14}+\frac{15}{56}=\frac{27}{56}$
The answer is: 27/56 or as a decimal fraction 0.482 or as a percentage 48.2%.