Question

x^2/3-3x^1/3-4=0
${x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0$

Answer 1

${x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0$
Solve using substitution
${t}^{2} - 3t - 4 = 0$
Solve the equation
$t = 4 \\ t = - 1$
Return the substituted values
${x}^{ \frac{1}{3} } = 4 \\ {x}^{ \frac{1}{3} } = - 1$
Solve the equations
$x = 64 \\ x = - 1$
The final solutions are,
$x1 = - 1 \\ x2 = 64$