Question

In a right triangle one of the legs is 3 cm smaller than the hypotenuse, and the other leg is 6 cm smaller than the hypotenuse. Find the length of the hypotenuse.

Answer 1

I used the formula: a^2 + b^2 = c^2
I'm pretty sure it doesn't matter which side 3 and 6 are on so I just said 3 was a and 6 was b.
I filled in the formula to: 3^2 + 6^2 = c^2
C is always the hypotenuse
Anyway, 3^2 is 3x3 which is 9.
6^2 is 6x6 which is 36
9+36=c
45=c
THEN you need to take the square root out of 45.
Since it doesn't fit in evenly, I got a long decimal but I rounded it to 6.71.
It makes sense to me because the hypotenuse always needs to have the biggest side. 
The answer is 6.71 if you don't feel like reading this long explanation.

Answer 2

Answer: 15cm

Step-by-step explanation:

You have put it as a quadratic Equatio first.

^ means exponential

x^2=(x-3)^2+(x-6)^2

then solve it and you will get the answer x=3, x=15 you have to choose the greatest answer because the hypotenuse has a bigger number than the legs.

So the answer is 15cm.