Question

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Answer 1

We have compound interests, so:

$a_1=600\\\\r=4\%=0.04$

and:

$A(n)=a_1(1+r)^{(n-1)}\\\\\boxed{A(n)=600(1+0.04)^{(n-1)}}\\\\\\A(5)=600(1+0.04)^{(5-1)}=600(1.04)^{4}=600\cdot1.17\approx\boxed{701.92}$

Answer B.