1. The equation is [tex]6-\log_8(x+7) = 5.[/tex]
Rearranging, we have [tex]\log_8(x+7) = 1.[/tex] We know that (x+7) must be 8, since [tex]\log_88=1[/tex], so we set the equation:
x+7=8, which means that x=1.
(quick check: [tex]6-\log_8(1+7) = 6-\log_8(8)=6-1=5.[/tex]
2.
The equation is [tex]\displaystyle{ 100(\frac{1}{5})^{\displaystyle{ \frac{x}{4}}}=4.[/tex]
Dividing both sides by 100, the right hand side becomes 1/25, which can be written as [tex]( \frac{1}{5} )^2[/tex].
Now that both exponential expressions have the same base, we set the exponents equal:
[tex]\displaystyle{ \frac{x}{4}}=2[/tex], which gives us x=8.
3.
The most well known natural logarithmic function is [tex]f(x)=\ln x[/tex] (that is: [tex]f(x)=\log_ex[/tex].)
The asymptote of this function is the line x=0. This means that we have to shift [tex]f(x)=\ln x[/tex] 5 units left, to get:
[tex]g(x)=\ln (x+5).[/tex]
Now, at 1, this function takes the value [tex]g(1)=\ln (1+5)=\ln (6).[/tex] To make the function pass through (1, 2), we could multiply by [tex] \displaystyle{ \frac{2}{\ln 6}.[/tex]
So, the function would be [tex]h(x)=\frac{2}{\ln 6} \ln (x+5).[/tex]
Answers:
1. 1
2. 8
3. [tex]h(x)= \frac{2}{\ln 6}\ln (x+5).[/tex]