Question

What is the length of side BC of the triangle?



Enter your answer in the box.

____ units

Answer 1

Answer:

28 units

Explanation:

This is an isosceles triangle.  We can tell this by the fact that the base angles, ∠C and ∠B, are marked congruent.

In an isosceles triangle, the two sides adjacent to the two congruent angles are also congruent.  This means that AC ≅ AB; it also gives us the equation

2x+7 = 4x-7

We do not want a variable on both sides, so we can start by subtracting 2x from each side:

2x+7-2x = 4x-7-2x

7 = 2x-7

Add 7 to both sides to cancel it on the right:

7+7 = 2x-7+7

14 = 2x

Divide both sides by 2:

14/2 = 2x/2

7 = x

The length of BC is 4x units; this means it is 4(7) = 28 units.

Answer 2

The length of side BC of the triangle is 28 units.

From the given diagram, we have an isosceles triangle. This is because the length of sides of the base angles has an equal length.

As such, we can say that:

• |AC| = |AB|

Since the adjacent sides are equal, the angles are also equal.

Thus,

∠AC = ∠ AB

Now;

|AC| = |AB|

2x + 7 = 4x - 7

If we subtract 2x from the both sides, we have:

2x + 7 - 2x = 4x - 7 - 2x

7 = 2x - 7

2x = 7 + 7

2x = 14

$\mathbf{x = \dfrac{14}{2}}$

x = 7

From the base of the triangle, line BC = 4x

|BC| = 4(7)

|BC| = 28 units

Therefore, we can conclude that the length of side BC is 28 units.

Learn more about the isosceles triangle here:

https://brainly.com/question/6238271?referrer=searchResults