Question

A-0.06 C charge that moves downward is in a uniform electric field with a strength of 200 N/C. What is the
magnitude and direction of the force on the charge?
O 12 Nup
O 12 N down
O 3333 Nup
O 3333 N down

Answer 1

Answer:

its B

Explanation:

i just took the test

Answer 2

The correct option is B. The magnitude of the force on the charge is 12N and the direction is downward.

The electric field is a region of space where electric force can be felt. The formula for calculating the magnitude of a force in an electric field is expressed as:

$\overline F=qE$ where:

• q is the charge measured in Coulombs
• E is the electric field intensity measured in N/C

Given the following parameters:

q = -0.06C

E = 200N/C

Substitute the given parameters into the formula as shown:

$\overline F = -0.06 * 200\\\overline F = -12N$

Since the modulus of the force is in the negative sense, hence the direction will be downward.

Learn more here: https://brainly.com/question/22735564