Question

How many s electrons does Ca+ possess?

Answer 1

The electron configuration of Ca is

1s2 2s2 2p6 3s2 3p6 4s2

So, since Ca+ has a positive charge, we know it has one less electron. Therefore the electron configuration is

1s2 2s2 2p6 3s2 3p6 4s1

You can take it from there. Just count the numbers next to each s and add them up

Answer 2

Explanation:

Atomic number of calcium is 20 and its electronic distribution is 2, 8, 8, 2. When an atom has a positive charge then it means the atom has lost some electrons.

And, if an atom has a negative charge then it means an atom has gained some electrons.

For example, $Ca^{+}$ has one positive charge which means one electron has been lost by the calcium atom.

Hence, total number of electrons present in $Ca^{+}$ are 19 and its electronic configuration will be $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}$.

Thus, we can conclude that there are 7 s electrons present in $Ca^{+}$.