To solve the given equation we will use the quadratic formula:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]In the given equation:
[tex]\begin{gathered} a=-1, \\ b=4, \\ c=-2. \end{gathered}[/tex]Substituting the above values in the formula, we get:
[tex]x=\frac{-4\pm\sqrt{16-4(-1)(-2)}}{2(-1)}.[/tex]Simplifying the above result, we get:
[tex]x=\frac{-4\pm\sqrt{8}}{-2}=2\pm\sqrt{2}.[/tex]