Respuesta :

To solve the given equation we will use the quadratic formula:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]

In the given equation:

[tex]\begin{gathered} a=-1, \\ b=4, \\ c=-2. \end{gathered}[/tex]

Substituting the above values in the formula, we get:

[tex]x=\frac{-4\pm\sqrt{16-4(-1)(-2)}}{2(-1)}.[/tex]

Simplifying the above result, we get:

[tex]x=\frac{-4\pm\sqrt{8}}{-2}=2\pm\sqrt{2}.[/tex]

Answer:

[tex]\begin{gathered} x_1=2-\sqrt{2}\approx0.59, \\ x_2=2+\sqrt{2}\approx3.41. \end{gathered}[/tex]

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