Question

Use Properties of Equality to solve

-3(4-a)=6

5(x+6)=45

Answer 1

Use distributive property: $a(b\pm c)=ab\pm ac$

$-3(4-a)=6\\\\(-3)(4)+(-3)(-a)=6\\\\-12+3a=6\ \ \ |add\ 12\ to\ both\ sides\\\\3a=18\ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=6}$


$5(x+6)=45\\\\(5)(x)+(5)(6)=45\\\\5x+30=45\ \ \ \ |subtract\ 30\ from\ both\ sides\\\\5x=15\ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{x=3}$