There are many ways in which we can find for the zeros of the problem. We can use the quadratic formula, completing the square, using a graphing calculator, etc.
For this problem, I'll be completing the square.
x² - 6x = -22
Since the constant has been moved to the right side already, we can move on to the next step which is adding (b/2)² to both sides of the equation.
x² - 6x + (-6/2)² = -22 + (-6/2)²
x² - 6x + 9 = -22 + 9
Factor the left side of the equation into a perfect square and simplify the right side.
(x - 3)(x - 3) = -13
Take the square of both sides.
x - 3 = ± √-13
Take out the negative from the square root as the letter "i"
x - 3 = ± i√13
Add 3 to both sides of the equation to let x be by itself.
x = 3 ± i√13
So your two roots will be:
x = 3 + i√13 and x = 3 - i√13
Solution: C. 3 - i√13
