Question

The average value of the function v(x)=6/x2 on the interval [1,c] is equal to 1. find the value of

Answer 1

∫6/x²=-6/x
F=-6/x
F(c)-F(1)=c
-6/x+6/1=c
c²-6c+6=0
D=36-4*6=12
c₁=(6-√12)/2=1.26795
c₂=(6+√12)/2=4.73205

C can be 1.26795
C can be 4.73205