Question

Calculate the molarity of a solution that contains 15.7g of caco3 dissolved in enough water to make 275 ml of solution

Answer 1

0.570 M (note the capital M, this is molarity. Using m denotes molality. Molarity is represented by moles of solute over the liters of solution. In this problem we are given the mass of the solute and volume of solution. The calculations is follows: (15.7 g CaCO3/275 mL of solution) x (1 mole CaCO3/ 100.0869 g of CaCO3) x (1000 mL of solution/ 1 L of solution) = 0.570 M CaCo3.

Answer 2

Taking into account the definition of molarity, the molarity of a solution that contains 15.7g of CaCO₃ dissolved in enough water to make 275 mL of solution is 0.57 $\frac{moles}{liter}$.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity= \frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$.

This case

In this case, you have:

• number of moles: $15.7 gramsx\frac{1 mole}{100 grams} = 0.157 moles$ , being 100 $\frac{grams}{mole}$ the molar mass of CaCO₃
• volume: 275 mL= 0.275 L, being 1000 mL= 1 L

Replacing in the definition of molarity:

$Molarity= \frac{0.157 moles}{0.275 L}$

Solving:

Molarity= 0.57 $\frac{moles}{liter}$

Finally, the molarity of a solution that contains 15.7g of CaCO₃ dissolved in enough water to make 275 mL of solution is 0.57 $\frac{moles}{liter}$.

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