Respuesta :

Answer:  The below graph shows the given function.

Step-by-step explanation:

Here the given function,

[tex]\frac{x^2+5x-6}{x^2-16}[/tex]

Which is the rational function.

For vertical asymptote,

Denominator = 0

⇒ [tex]x^2 - 16 = 0[/tex]

⇒  [tex]x^2 = 16[/tex]

⇒   [tex]x = \pm 4[/tex]

Thus, the vertical asymptotes of the given function are (4, 0) and (-4,0).

Also, x-intercept of the given function are ( 1,0) and  (-6,0)

y-intercept of the given function are (0,0.375)

End behavior :

Since, The function has three intervals,

[tex](-\infty, -4)[/tex]

[tex](-4,4)[/tex]

[tex](-\infty, -4)[/tex]

In interval [tex](-\infty, -4)[/tex] , [tex]f(x)\rightarrow 1[/tex] as [tex]x \rightarrow -\infty[/tex] and [tex]f(x)\rightarrow -\infty[/tex] as [tex]x \rightarrow -4[/tex]

In interval [tex](-4,4)[/tex], [tex]f(x)\rightarrow \infty[/tex] as [tex]x \rightarrow -4[/tex] and [tex]f(x)\rightarrow -\infty[/tex] as [tex]x \rightarrow 4[/tex]

And, In interval [tex](-\infty, -4)[/tex],  [tex]f(x)\rightarrow \infty[/tex] as [tex]x \rightarrow 4[/tex] and [tex]f(x)\rightarrow 1[/tex] as [tex]x \rightarrow \infty[/tex]




Ver imagen parmesanchilliwack
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