Answer: The below graph shows the given function.
Step-by-step explanation:
Here the given function,
[tex]\frac{x^2+5x-6}{x^2-16}[/tex]
Which is the rational function.
For vertical asymptote,
Denominator = 0
⇒ [tex]x^2 - 16 = 0[/tex]
⇒ [tex]x^2 = 16[/tex]
⇒ [tex]x = \pm 4[/tex]
Thus, the vertical asymptotes of the given function are (4, 0) and (-4,0).
Also, x-intercept of the given function are ( 1,0) and (-6,0)
y-intercept of the given function are (0,0.375)
End behavior :
Since, The function has three intervals,
[tex](-\infty, -4)[/tex]
[tex](-4,4)[/tex]
[tex](-\infty, -4)[/tex]
In interval [tex](-\infty, -4)[/tex] , [tex]f(x)\rightarrow 1[/tex] as [tex]x \rightarrow -\infty[/tex] and [tex]f(x)\rightarrow -\infty[/tex] as [tex]x \rightarrow -4[/tex]
In interval [tex](-4,4)[/tex], [tex]f(x)\rightarrow \infty[/tex] as [tex]x \rightarrow -4[/tex] and [tex]f(x)\rightarrow -\infty[/tex] as [tex]x \rightarrow 4[/tex]
And, In interval [tex](-\infty, -4)[/tex], [tex]f(x)\rightarrow \infty[/tex] as [tex]x \rightarrow 4[/tex] and [tex]f(x)\rightarrow 1[/tex] as [tex]x \rightarrow \infty[/tex]