A particle moving uniformly along the x axis is located at 11.3m at 0.588s and at 3.38m at 4.67s. Find its displacement during this time interval.

Respuesta :

7.92 meters, since its very clear that the particle at 4.67 seconds it was opposing the initial direction therefore you can say 11.3m - 3.387m and get your answer
AL2006
Displacement = (distance between start and end points) in the direction of (direction from start to end point). Distance = (11.3-3.38)= 7.92 m. Direction = the negative 'x' direction.
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