Given that For
a certain model of car the distance [tex]d[/tex] required to stop the vehicle if
it is traveling at [tex]v[/tex] mi/h is given by the formula [tex]d=v+\frac{v^2}{20}, where [tex]d [/tex]
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
[tex]v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30[/tex]
Therefore, the range of speed she can travel is [tex]v\leq30\ mi/hr[/tex]