Answer:The mass of the lead cylinder is 1,995.898 g.
Explanation:
Radius of the cylinder,r =[tex]\frac{Diameter}{2}=\frac{1.80 inches}{2}=0.9 inches[/tex]
Height of the cylinder,h = 4.12 inches
Volume of the cylinder: [tex]\pi r^2h=3.14\times (0.9 inches)^2\times 4.12 inches=10.47 inches^3[/tex]
[tex]inches^3=16.3871 ml[/tex]
Volume of the cylinder in ml= [tex]10.47\times 16.3871 ml=171.57 ml[/tex]
Density of the lead cylinder = 11.4 g/ml
[tex]density=\frac{Mass}{Volume}[/tex]
[tex]Mass=11.4 g/ml\times 171.57 ml=1,955.898 g[/tex]
The mass of the lead cylinder is 1,995.898 g.
