Answer:
[tex]C_3H_5O_2[/tex] the empirical formula of a compound.
Explanation:
Suppose in 100 g of compound contains 50.0% carbon, 6.7% hydrogen, and 43.3% oxygen;
Then mass of carbon = [tex]100\%\times \frac{50.0}{100}=50.0 g[/tex]
Moles of carbon =[tex]\frac{50.0 g}{12 g/mol}=4.16 mol[/tex]
Then mass of hydrogen= [tex]100\%\times \frac{6.7}{100}=6.7 g g[/tex]
Moles of hydrogen=[tex]\frac{6.7 g}{1 g/mol}=6.70 mol[/tex]
Then mass of oxygen = [tex]100\%\times \frac{43.3}{100}=43.3 g[/tex]
Moles of oxygen =[tex]\frac{43.3 g}{16 g/mol}=2.70 mol[/tex]
To determine the empirical formula compound dived the smallest value of moles from each moles of element.
Carbon = [tex]\frac{4.1666 mol}{2.7062 mol}=1.5[/tex]
Hydrogen= [tex]\frac{6.70 mol}{2.7062 mol}=2.5[/tex]
Oxygen= [tex]\frac{2.7062 mol}{2.7062 mol}=1[/tex]
The empirical formula ;[tex]C_{1.5}H_{2.5}O_{1}=C_3H_5O_2[/tex]
[tex]C_3H_5O_2[/tex] the empirical formula of a compound.
