Answer:
B) [tex]x\geq0[/tex]
Step-by-step explanation:
The domain of the square root function is all real non-negative numbers. In a numerical format that is as follows:
[tex]D(\sqrt{x})={[0,\infty )}[/tex]
This is more commonly denoted as:
[tex]x\geq0[/tex]
In the case of the given function:
[tex]g(x)=\sqrt{8x}[/tex]
The domain is still ([tex]x\geq0[/tex]) as multiplying a value by (8) does not alter this. A negative number times (8) is still negative and thus cannot be a part of the square root domain. Similarly, a positive number times (8) is still positive and remains a part of the square root domain. Moreover, (0) times (8) is still (0).
