The empirical formular of 55.3%of K

Alright, so when we talk about the empirical formula of a compound, we're basically describing the simplest whole number ratio of atoms present in that compound. So, if we're looking at a substance that's 55.3% potassium (K), what we're saying is that out of all the atoms in the compound, 55.3% of them are potassium atoms.

Now, to find the empirical formula, we need to figure out the ratio of potassium atoms to other atoms present in the compound. Since it's just potassium in this case, we don't need to worry about any other elements. So, if 55.3% of the compound is potassium, it means that the remaining percentage must be something else, but since we only have potassium, that remaining percentage is 100% - 55.3%, which equals 44.7%.

Now, because we want the simplest whole number ratio, we need to convert these percentages into ratios that can be represented by small integers. So, if we divide both percentages by their respective atomic masses (39.10 g/mol for potassium), we get the molar ratio. For potassium, it's:

55.3% K ÷ 39.10 g/mol = 1.415 moles of K

And for the other element (which we don't know yet), it's:

44.7% ÷ molar mass of the other element

We don't have the molar mass of the other element, so we can't determine the exact ratio without further information. But the empirical formula would be K1.X, where X represents the other element, and the subscript 1 signifies that there's only one atom of potassium in each formula unit.