When silver nitrate reacts with sodium chloride, it produces silver chloride and sodium nitrate. The chemical reactions contains a one to one ratio of each compound on the reactant side and the products side.
In order to determine the correct answer, we must first convert the 25.0 milliliters to moles using:
moles = concentration * volume.
25 ml = 0.025 L
Moles of both reactants = 0.25 * 1 = 0.025
Now we have to calculate the mass of AgCl which is found by adding the atomic weight of silver and chlorine. The mass of AgCl is 143.3 g/mol. Multiplying 143.3 g/mol by 0.025 moles results in a mass of 3.58 grams of AgCl being produced.
