A student whose mass is 60 kg and a bicycle with
a mass of 20 kg are at rest on a horizontal road.
The student exerts a force of 120 N to accelerate
the bike over a distance of 48 meters. What is the
velocity of the bicycle and rider at the end of the
48 meters?
a) 3 m/s
b) 6 m/s
c) 8 m/s
d) 12 m/s

Respuesta :

Answer:

d) 12 m/s

Explanation:

Work = change in energy

W = KE

Fd = ½ mv²

(120 N) (48 m) = ½ (60 kg + 20 kg) v²

v = 12 m/s

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