Respuesta :
Refer to the histogram shown below.
Total frequency = 44 + 1515 + 1818 + 66 + 11 = 3454.
Calculate relative frequencies, to the nearest thousandth.
Class a:
44/3454 = 0.0127
Answer: 0.013
Class b:
1515/3454 = 0.4386
Answer: 0.439
Class c:
1818/3454 = 0.5263
Answer: 0.526
Class d:
66/3454 = 0.0191
Answer: 0.019
Class f:
11/3454 = 0.0032
Answer: 0.003
Total frequency = 44 + 1515 + 1818 + 66 + 11 = 3454.
Calculate relative frequencies, to the nearest thousandth.
Class a:
44/3454 = 0.0127
Answer: 0.013
Class b:
1515/3454 = 0.4386
Answer: 0.439
Class c:
1818/3454 = 0.5263
Answer: 0.526
Class d:
66/3454 = 0.0191
Answer: 0.019
Class f:
11/3454 = 0.0032
Answer: 0.003

The relative frequency for the class 'a' is 0.013, the relative frequency for the class 'b' is 0.439, the relative frequency for the class 'c' is 0.527, the relative frequency for the class 'd' is 0.019, the relative frequency for the class 'f' is 0.00319.
What is a relative frequency?
It is defined as the ratio of the frequency that can be evaluated by the two-way frequency table. Usually, we can obtain this frequency by dividing the frequency that is not in the total frequency cell to total frequency.
We have a frequency table of grades has five classes:
a , b , c, d, f with frequencies
44, 1515, 1818, 66, 11
Sum of the frequency = 44 + 1515 + 1818 + 66 + 11
= 3454
Relative frequency for class a = 44/3454 ⇒ 0.0127 ≈ 0.013
Relative frequency for class b = 1515/3454 ⇒ 0.4386 ≈ 0.439
Relative frequency for class c = 1818/3454⇒ 0.5263≈ 0.527
Relative frequency for class d = 66/3454 ⇒ 0.0191≈ 0.019
Relative frequency for class f = 11/3454 ⇒ 0.003184≈ 0.00319
Thus, the relative frequency for the class 'a' is 0.013, the relative frequency for the class 'b' is 0.439, the relative frequency for the class 'c' is 0.527, the relative frequency for the class 'd' is 0.019, the relative frequency for the class 'f' is 0.00319.
Learn more about the relative frequency here:
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