Question

If g(t)=(3t-5)^2+4t-1, find expressions for each of the following:
(a) g(a)
(b) g(a+2)

Answer 1

you have only exchange every t to a
g(a)= (3a-t5)^2+4a-1
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and here every t by a+2
g(a+2)=(3(a+2)-5)^2+4(a+2)-1
=(3a+2-5)^2+4a+8-1
=(3a-3)^2+4a+7