Certainly! When you throw a single die twice, each throw is independent of the other.
The probability of getting a 3 on the first throw is 1/6 because there is one favorable outcome (getting a 3) out of six possible outcomes (numbers 1 through 6).
Now, given that you have already thrown a 3 on the first throw, the probability of getting an odd number on the second throw is 1/2 because there are three odd numbers (1, 3, 5) out of six possible outcomes.
To find the probability of both events occurring (getting a 3 on the first throw and then getting an odd number on the second throw), you multiply the probabilities:
Probability of 3 and then an odd number = Probability of 3 * Probability of odd number given that a 3 has already been thrown = (1/6) * (1/2) = 1/12
So, the probability of first getting a 3 and then getting another odd number is 1/12.
